2nd parameter of hidn packet

[Roxeez]

Hi, i'm wondering if somebody know how can we get a hidden area position using hidn packet

hidn 0 1.49 23 105

Since 3rd & 4th parameters is character position, i need a way to find hidden area "position" using 2nd parameter.

If somebody know how it's calculated or something, i would like to know thanks

[romdrak]

Hey, I had the same problem, when I worked on pts bot. It's the angle of the arrow in radians from +x axis (clockwise). Took me few hours to figure it out

and then you can calculate coordinates using matrix or something like that
(again python example )

 Spoiler

def calculate_pts_position(a: Vertex2D, a_angle: float, b: Vertex2D, b_angle: float):
    # a: first point, b: second point
    # calculating matrix
    params = np.linalg.inv(
        np.array([[np.cos(a_angle), np.cos(b_angle)],
                  [np.sin(a_angle), np.sin(b_angle)]])) \
                      .dot(np.array([b.x-a.x, b.y-a.y]))

    # calculating final position
    x = int(a.x + params[0] * np.cos(a_angle))
    y = int(a.y + params[0] * np.sin(a_angle))
    return Vertex2D(x, y)

[Roxeez]

Originally Posted by romdrak

Hey, I had the same problem, when I worked on pts bot. It's the angle of the arrow in radians from +x axis (clockwise). Took me few hours to figure it out

and then you can calculate coordinates using matrix or something like that
(again python example )

 Spoiler

def calculate_pts_position(a: Vertex2D, a_angle: float, b: Vertex2D, b_angle: float):
    # a: first point, b: second point
    # calculating matrix
    params = np.linalg.inv(
        np.array([[np.cos(a_angle), np.cos(b_angle)],
                  [np.sin(a_angle), np.sin(b_angle)]])) \
                      .dot(np.array([b.x-a.x, b.y-a.y]))

    # calculating final position
    x = int(a.x + params[0] * np.cos(a_angle))
    y = int(a.y + params[0] * np.sin(a_angle))
    return Vertex2D(x, y)

Thanks for your help

[ctyjason2]

Originally Posted by romdrak

Hey, I had the same problem, when I worked on pts bot. It's the angle of the arrow in radians from +x axis (clockwise). Took me few hours to figure it out

and then you can calculate coordinates using matrix or something like that
(again python example )

 Spoiler

def calculate_pts_position(a: Vertex2D, a_angle: float, b: Vertex2D, b_angle: float):
    # a: first point, b: second point
    # calculating matrix
    params = np.linalg.inv(
        np.array([[np.cos(a_angle), np.cos(b_angle)],
                  [np.sin(a_angle), np.sin(b_angle)]])) \
                      .dot(np.array([b.x-a.x, b.y-a.y]))

    # calculating final position
    x = int(a.x + params[0] * np.cos(a_angle))
    y = int(a.y + params[0] * np.sin(a_angle))
    return Vertex2D(x, y)

what is a_angle and b_angle

[romdrak]

You need to have at least 2 these packets from different positions to get the final position of pts. (a - first, b - second)

[ctyjason2]

Originally Posted by romdrak

You need to have at least 2 these packets from different positions to get the final position of pts. (a - first, b - second)

is that means we need to calculate the angle first?
the angle a is the angle of point a to b and angle b is the angle of point b to a?

[romdrak]

Originally Posted by ctyjason2

is that means we need to calculate the angle first?
the angle a is the angle of point a to b and angle b is the angle of point b to a?

No, you need 2 hidn packets which looks like hidn 0 {angle} {pos_x} {pos_y} (they need to have different positions and angles)